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When the current in a coil changes from 8 A to 2 A in 3×10-2 s the e.m.f. induced in the coil is 2 volt. The self-inductance of the coil (in millihenry) is

a
1
b
5
c
20
d
10

detailed solution

Correct option is D

e=-Ldidt⇒2=-L2-83×10-2⇒L=0.01H=10mH

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