When the current in a coil changes from 8 A to 2 A in 3×10-2 s the e.m.f. induced in the coil is 2 volt. The self-inductance of the coil (in millihenry) is
1
5
20
10
e=-Ldidt⇒2=-L2-83×10-2
⇒L=0.01H=10mH