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Questions  

When a current of (2.5±0.5)A flows through a wire, it develops a potential difference of (20±1)V. The resistance of wire is

a
(8±2)Ω
b
(8±1.6)Ω
c
(8±1.5)Ω
d
(8±3)Ω

detailed solution

Correct option is A

We know resistance R=Vl=202.5=8  ΩΔRR=ΔVV+Δll=120+0.52.5=14ΔR=14×8=2  Ω=R(8±2)Ω

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