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When a d.c. source V0 volt is connected across an inductor, power dissipated is P. When an a.c. source having peak value V0 is connected across the same inductor, average power consumed is P/4. Then power factor of the inductor is

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answer is 3.

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Detailed Solution

V02R=P and (V02)(V02Z).RZ=P/4∴ V02R2 Z2=V024R⇒ Z2=2R2⇒R2+XL2=2R2⇒XL=R∴ cos⁡ϕ=RZ=RR2+R2=12

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