When electric bulbs of same power, but different marked voltage are connected in series across the power line, their brightness will be
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a
proportional to their marked voltage
b
inversely proportional to their marked voltage
c
proportional to the square of their marked voltage
d
inversely proportional to the square of their marked voltage
answer is C.
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Detailed Solution
Resistance of bulb R=V2P, where V is the marked voltage and P is the marked power. P is same for both. As both bulbs are connected in series, so current in both of them will be same. So, brightness ∝ R ∝ V2.