Questions
When electric bulbs of same power, but different marked voltage are connected in series across the power line, their brightness will be
detailed solution
Correct option is C
Resistance of bulb R=V2P, where V is the marked voltage and P is the marked power. P is same for both. As both bulbs are connected in series, so current in both of them will be same. So, brightness ∝ R ∝ V2.Talk to our academic expert!
Similar Questions
Permissible current through a fuse wire of diameter 1 mm is 1A. What should be the radius of a fuse wire, made of same material, whose permissible current is 8A ?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
