When electric bulbs of same power, but different marked voltage are connected in series across the power line, their brightness will be

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proportional to their marked voltage

inversely proportional to their marked voltage

proportional to the square of their marked voltage

inversely proportional to the square of their marked voltage

answer is C.

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Detailed Solution

Resistance of bulb R=V2P, where V is the marked voltage and P is the marked power. P is same for both. As both bulbs are connected in series, so current in both of them will be same. So, brightness ∝ R ∝ V2.

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