When the electron of He+ jumps from third excited state to first exited state, a monochromatic radiation is emitted. When this radiation irradiates a photo sensitive material, the stopping potential is found to be 6.2 volt. Then threshold wavelength of the material is
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answer is 3.
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Detailed Solution
Energy of emitted photon, hν=13.6 x 22 x 122-142 eV=10.2 eV∴10.2=ϕ+6.2⇒ϕ=4 eV∴hcλ0=ϕ⇒λ0=hcϕ=124004Ao=3100 Ao