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Q.

When the electron in the hydrogen atom jumps from 2nd orbit to 1st orbit, the wavelength of radiation emittedis λ. When the electrons jump from 3rd orbit to 1st orbit, the wavelength of emitted radiation would be

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a

2732λ

b

3227λ

c

23λ

d

32λ

answer is A.

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Detailed Solution

1λ=R1n12−1n22First Condition 1λ=R112−122⇒R=43λSecond Condition1λ'=R112−132⇒λ'=98R⇒λ'=98×43λ=27λ32
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