When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface increased from 0.5 eV to 0.8 eV. The work function of the metal is

According to Einstein's photoelectric equation, The kinetic energy of emitted photoelectrons is K=hv-ϕ0where hν is the energy of incident radiation and ϕ0 is work function of the metal. As per question, As per question,0.5eV=hv-ϕ0  ......................(i)0.8eV=1.2hv-ϕ0  .................(ii)            On solving eqns. (i) and (ii), we get ϕ0=1.0eV