Questions
When an engine passes near to a stationary observer then its apparent frequencies occurs in the ratio 5/3. If the velocity of engine is
detailed solution
Correct option is C
When engine approaches towards observer n'=n vv−vswhen engine going away from observer n''=vv+vSn∴n'n''=v+vsv−vs⇒53=340+vs340−vs⇒vs=85 m/sTalk to our academic expert!
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