Questions
When a force is applied to a spring of force constant K, elongation produced in the spring is x. When the force is slowly increased to twice is present value, work done on the spring will be
detailed solution
Correct option is C
F=K·x, 2F=K·x1⇒x1=2FK∴ Work done =12Kx12-12Kx2=12K2FK2-12K·FK2=3F22K=3(Kx)22K=32Kx2Talk to our academic expert!
Similar Questions
Two similar springs P and Q have spring constants such that Kp > . They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs are related as, in case (a) and case (b), respectively.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
