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Q.

When a force is applied on a wire of uniform crosssectional area 3 x 10-6m2 and length 4 m, the increase in length is I mm. Energy stored in it will be (Y = 2 x 1011 N/m2)

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a

6250 J

b

0.177 J

c

0.075 J

d

0.150 J

answer is C.

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Detailed Solution

U = 12×YAl2L = 12×2×1011×3×10-6×(1×10-3)24     = 0.075 J
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When a force is applied on a wire of uniform crosssectional area 3 x 10-6m2 and length 4 m, the increase in length is I mm. Energy stored in it will be (Y = 2 x 1011 N/m2)