When a galvanometer having coil resistance 100Ω is converted into ammeter, 90% of the main current is by passed through the shunt, then resistance of the ammeter is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
10 Ω
b
5 Ω
c
90 Ω
d
9 Ω
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Rsh×0.9 I=100×0.1 I⇒ Rsh=100/9 Ω∴ Resistance of ammeter=100×1009(100+1009)Ω=10Ω
When a galvanometer having coil resistance 100Ω is converted into ammeter, 90% of the main current is by passed through the shunt, then resistance of the ammeter is