When a glass prism of refracting angle 60° is immersed in a liquid its angle of minimum deviation is 30°. The critical angle of glass with respect to the liquid medium is
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a
42°
b
45°
c
50°
d
52°
answer is B.
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Detailed Solution
A=60∘,δm=30∘ so μ=sinA+δm2sinA2 μ=sin60∘+30∘2sin60∘2=sin45∘sin30∘=2 Also μ=1sinC⇒C=sin−11μ⇒C=45∘