First slide

Change in internal energy

Question

When an ideal diatomic gas is heated at constant pressure,the fraction of the heat energy supplied which increases the internal energy of the gas, is:

Easy

A

$\frac{2}{5}$
B

$\frac{3}{5}$
C

$\frac{3}{7}$
D

$\frac{5}{7}$

Solution

$\frac{∆ U}{Q} = \frac{{nC}_{V} ∆ T}{{nC}_{P} ∆ T} = \frac{1}{γ} = \frac{f}{f + 2} = \frac{5}{5 + 2} = \frac{5}{7}$

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