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When an ideal gas is expanded adiabatically to eight times its initial volume, its temperature is reduced to four times its initial temperature. Then the ratio for the gas is
detailed solution
Correct option is B
For adiabatic process TV1−δ=constant∴ V2V1δ−1=T1T2⇒8δ−1=4⇒23δ−1=22∴ 3δ−1=2⇒δ=53Now CV=Rδ−1⇒CVR=153−1=32Talk to our academic expert!
Similar Questions
During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of for the gas is
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