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Q.

When an ideal gas is expanded adiabatically to eight times its initial volume, its temperature is reduced to four times its initial temperature. Then the ratio CVR for the gas is

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a

52

b

32

c

3

d

35

answer is B.

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Detailed Solution

For adiabatic process TV1−δ=constant∴ V2V1δ−1=T1T2⇒8δ−1=4⇒23δ−1=22∴ 3δ−1=2⇒δ=53Now CV=Rδ−1⇒CVR=153−1=32
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