First slide

Heat engine

Question

When an ideas gas (r = 7/3) is heated under constant pressure, then what percentage of given heat energy will be utilised is doing external work

Moderate

A

43%
B

57%
C

29%
D

40%

Solution

$\begin{array}{l} Δ Q = ΔU + ΔW \Rightarrow \frac{ΔW}{ΔQ} = 1 - \frac{ΔU}{ΔQ} \\ \Rightarrow \frac{ΔW}{ΔQ} = 1 - \frac{{nC}_{v} ΔT}{{nC}_{v} ΔT} \\ = 1 - \frac{3}{7} = \frac{4}{7} \approx 0 .57 \end{array}$

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