First slide

First law of thermodynamics

Question

When 110 J of heat is added to a gaseous system, internal energy increases by 40 J, the amount of work done is:

Easy

A

150 J
B

70 J
C

110 J
D

40 J

Solution

dQ = du + dw
dw = dQ - du= 110-40=70 joule.

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