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When a 1.0 kg mass hangs attached to a spring of length 50 cm, the spring stretches by 2 cm. The mass is pulled down until the length of the spring becomes 60 cm. What is the amount of elastic energy stored in the spring (in J) in this condition, if g = 10 m/s2

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answer is 2.5.

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Detailed Solution

Force constant of a springk=Fx=mgx=1×102×10−2⇒k=500 N​/​mIncrement in the length = 60 – 50 = 10 cm U=12kx2=12500 (10×10−2)2=2.5 J
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When a 1.0 kg mass hangs attached to a spring of length 50 cm, the spring stretches by 2 cm. The mass is pulled down until the length of the spring becomes 60 cm. What is the amount of elastic energy stored in the spring (in J) in this condition, if g = 10 m/s2