When a 1.0kg mass hangs attached to a spring of length 50 cm, the spring stretches by 2 cm. The mass is pulled down until the length of the spring becomes 60 cm. What is the amount of elastic energy stored in the spring in this condition, if g = 10 m/s2
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a
1.5 Joule
b
2.0 Joule
c
2.5 Joule
d
3.0 Joule
answer is C.
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Detailed Solution
Force constant of a springk=Fx=mgx=1×102×10−2⇒k=500N/mIncrement in the length = 60 – 50 = 10 cm U=12kx2=1250010×10−22=2.5J