When $$0.400$$ kg of water at $$300C$$ is mixed with $$0.150$$ kg of water at $$250C$$ contained in a calorimeter, the final temperature is found to be $$270C$$ , find the water equivalent of the calorimeter.

Question

When $$0.400$$ kg of water at $$300C$$ is mixed with $$0.150$$ kg of water at $$250C$$ contained in a calorimeter, the final temperature is found  to be $$270C$$ , find the water equivalent of the calorimeter.

Infinity Learn · Accepted Answer

Water of mass $$m1$$ $$=$$ $$0.150$$ kg is taken in the calorimeter at temperature $$T1$$ $$=$$ $$250C$$ is mixed with N another known mass of pure water $$m2$$ $$=$$ $$0.400$$ kg at a temperature $$T2$$ $$=$$ $$300C$$ and final temperature is found to be T $$=$$ $$270C$$. Let sw and W be the heat capacity of water and the water equivalent of the calorimeter.Heat gained by (water$$ $$+$$ $$calorimeter) at temperature $$T1$$ $$=$$ Heat lost by water at temperature $$T2i$$.e., $$m1sw(T-T1)+Wsw(T-T1)$$ $$=$$ $$m2sw(T2-T)$$     or    W $$=$$ $$m2(T2-TT-T1)-m1Hence$$, W $$=$$ $$0.400$$ kg [$$300C-270C270C-250C$$] $$-$$ $$0.150$$ kg                 $$=$$ $$0.450$$ kg

When 0.400 kg of water at $30^{0} C is mixed with 0.150 kg of water at 25^{0} C contained in a calorimeter,$ $the final temperature$ $is found$
$to be 27^{0} C$ , find the water equivalent of the calorimeter.

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When 0.400 kg of water at 300C is mixed with 0.150 kg of water at 250C contained in a calorimeter, the final temperature is found to be 270C , find the water equivalent of the calorimeter.

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

When 0.400 kg of water at $30^{0} C is mixed with 0.150 kg of water at 25^{0} C contained in a calorimeter,$ $the final temperature$ $is found$
$to be 27^{0} C$ , find the water equivalent of the calorimeter.