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When a lens of power P (in air) made of material of refractive index 3 is dipped in a liquid of refractive index 4, the new power of lens is

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a

−4P3

b

P8

c

3P4

d

−P8

answer is D.

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Detailed Solution

P=(3−1)1R1−1R2=21R1−1R2 P′=34−11R1−1R2=−141R1−1R2=−P8

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