When light rays are incident on a prism at an angle of 45°, the minimum deviation is obtained. If refractive index of the material of prism is 2, then the angle of prism will be
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a
30°
b
40°
c
50°
d
60°
answer is D.
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Detailed Solution
sinA+δm2sinA2=μ, But A+δm2=i=45∘ So sin45∘sin(A/2)=2⇒12=sinA2⇒A=60∘
When light rays are incident on a prism at an angle of 45°, the minimum deviation is obtained. If refractive index of the material of prism is 2, then the angle of prism will be