First slide

Photoelectric effect and study of photoelectric effect

Question

When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, however light of 600 nm wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

Easy

Solution

$\begin{array}{l} Work function = \frac{h c}{λ_{0}}; where λ_{0} is threshold wavelength. \\ ∴ \frac{W_{0_{1}}}{W_{0_{2}}} = \frac{λ_{0_{2}}}{λ_{0_{1}}} = \frac{2}{1} \end{array}$

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