When the load on a wire is slowly increases from 3 to 5 kg-wt, the elongation increases from 0.61 to 1.02 mm. The work done during the extension of wire is:
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a
0.16 J
b
0.016 J
c
1.6 J
d
16 J
answer is B.
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Detailed Solution
Work done = 12 stretching force ×extension.Net work done in increasing the length from 0.164 mm to 1.02 mm isW2-W1 = 12×5×9.8×1.02×10-3-12×3×0.61×9.8×10-3 = 0.016 JSo the correct choice is (2).