When a metallic surface is illuminated with monochromatic light of wavelengthλ stopping potential for photoelectric current is 3V0. When the same metallic surface is illuminated with a light of wavelength 2λ the stopping potential is V0. The threshold wavelength for the surface is
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a
6 λ
b
4 λ
c
4λ3
d
8 λ
answer is B.
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Detailed Solution
hcλ =hcλ0+3eV0---1 hc2λ =hcλ0+e V0----2 solving we get λ0= 4λ