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Q.

When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength  2λ, the stopping potential is V4 . The threshold wavelength for the metallic surface is

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a

52λ

b

3λ

c

4λ

d

5λ

answer is B.

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Detailed Solution

According to Einstein’s photoelectric equation,eVs=hcλ−hcλ0 ∴ As per question, eV=hcλ−hcλ0 eV4=hc2λ−hcλ0From equations (i) and (ii), we gethc2λ−hc4λ=hcλ0−hc4λ0⇒hc4λ=3hc4λ0 or λ0=3λ
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