When a metallic surface is illuminated with radiation of wavelength $λ$ , the stopping potential is V. If the same surface is illuminated with radiation of wavelength
2 $λ$ , the stopping potential is $\frac{V}{4}$ . The threshold wavelength for the metallic surface is

Question

When a metallic surface is illuminated with radiation of wavelength $λ$ , the stopping potential is V. If the same surface is illuminated with radiation of wavelength

2 $λ$ , the stopping potential is $\frac{V}{4}$ . The threshold wavelength for the metallic surface is

Infinity Learn · Accepted Answer

According to Einstein’s photoelectric equation,$$eVs=hc$$λ−hcλ$$0$$ ∴ As per question, $$eV=hc$$λ−hcλ$$0$$ $$eV4=hc2$$λ−hcλ$$0From$$ equations (i) and (ii), we $$gethc2$$λ−$$hc4$$λ$$=hc$$λ$$0$$−$$hc4$$λ$$0$$⇒$$hc4$$λ$$=3hc4$$λ$$0$$ or λ$$0=3$$λ

When a metallic surface is illuminated with radiation of wavelength $λ$ , the stopping potential is V. If the same surface is illuminated with radiation of wavelength
2 $λ$ , the stopping potential is $\frac{V}{4}$ . The threshold wavelength for the metallic surface is

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When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2λ, the stopping potential is V4 . The threshold wavelength for the metallic surface is

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When a metallic surface is illuminated with radiation of wavelength $λ$ , the stopping potential is V. If the same surface is illuminated with radiation of wavelength
2 $λ$ , the stopping potential is $\frac{V}{4}$ . The threshold wavelength for the metallic surface is