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Q.

When a metallic surface is illuminated with radiation of wavelength λ  the stopping potential is v. If the same surface is illuminated with radiation of wavelength 2λ the stopping potential is V4, The threshold wavelength for the metallic surface is

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a

52λ

b

3λ

c

4λ

d

5λ

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Detailed Solution

According to Einstein's photoelectric equation, eVs=hcλ-hcλ0∴ As per question, eV=hcλ-hcλ0……..(i)eV4=hc2λ-hcλ0……(ii)From equations (i) and (ii), we gethc2λ-hc4λ=hcλ0-hc4λ0⇒hc4λ=3hc4λ0   or   λ0=3λ
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