Q.
When the number of turns in a coil is doubled without any change in the length of the coil, its self-inductance
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a
becomes four times
b
is doubled
c
is halved
d
is unchanged
answer is A.
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Detailed Solution
L∝N2, i.e., L1L2=N1N22⇒L2=L1N2N12=4L1
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