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Q.

When an object is placed at a distance of 25cm from mirror, the magnification is m1. When object is moved 15cm farther away with respect to earlier position, the magnification becomes m2.  If m1m2=4 then focal power of mirror is

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a

0.5D

b

5D

c

−0.5D

d

−5D

answer is B.

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Detailed Solution

m=(ff−u) m1=(ff−u1)----(1) m2=(ff−u2)----(2) (1)/(2) ⇒4=f+40f+25⇒4f+100=f+403f=−60⇒f=−20cmP=−100f=+5D
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