When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60° with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30° and the same object is shot with the same velocity, it can travel x2 distance. Then, x1 : x2 will be
The motion of the object shot in two cases can be depicted as below
Using third equation of motion,
As the object stops finally, so v = 0
For inclined motion, g = gsin and h = x
Substituting these values in Eq. (i), we get
For case I
For case II