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Q.

When one of the slits in Young's experiment covered with a transparent sheet of thickness 3.6×10−3 cm the central fringe shifts to a position originally occupied by the 30th bright fringe. If λ=6000Å, the refractive index of the sheet is

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a

1.50

b

1.55

c

1.60

d

1.65

answer is A.

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Detailed Solution

The position of the 30th bright fringe is given byy30=30λDdHence the shift of the central fringe isy0=30λDd But y0=Dd(μ−1)t∴30λDd=Dd(μ−1)t or (μ−1)=30λt=30×6000×10−103.6×10−5=0.5∴ μ=1.5

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