Download the app

Questions  

When a particle of mass m is suspended from a massless spring of natural length , the length of the spring becomes 2 . When the same mass moves in conical pendulum as shown in figure, the length of the spring becomes L. The radius of the circle of conical pendulum is:

a
LL−ℓL(L−ℓ)
b
LL−ℓL(L−2ℓ)
c
L(L−ℓ)
d
L2−2ℓ2

detailed solution

Correct option is B

mg=kℓ           (1)k(L−ℓ)1−R2L2=kℓ  (2)1−R2L2=ℓ2(L−ℓ)2{(L−ℓ)2−ℓ2(L−ℓ)2}L2=R2R=(LL−ℓ)  (L2−2Lℓ)

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A block of mass m is revolving in a smooth horizontal plane with a constant speed v. If the radius of the circular path is R, find the total contact force received by the block.


phone icon
whats app icon