Q.
When a particle of mass m is suspended from a massless spring of natural lengthℓ , the length of the spring becomes 2ℓ . When the same mass moves in conical pendulum as shown in figure, the length of the spring becomes L. The radius of the circle of conical pendulum is:
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a
LL−ℓL(L−ℓ)
b
LL−ℓL(L−2ℓ)
c
L(L−ℓ)
d
L2−2ℓ2
answer is B.
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Detailed Solution
mg=kℓ (1)k(L−ℓ)1−R2L2=kℓ (2)1−R2L2=ℓ2(L−ℓ)2{(L−ℓ)2−ℓ2(L−ℓ)2}L2=R2R=(LL−ℓ) (L2−2Lℓ)
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