When the percentage Modulation is 75, an AM transmitter produces 10 kW Power. The percentage power saving if carrier and one of the side band is suppressed is

Given   :  % of modulation = 75 %                      ∴ m = 0.75  and  Transmitter power : Pt= 10 KW  Use, Pc = Pt1+m22 = 101.28=7.8 kW  We know that, Pt = Pc + PLSB +PUSB ⇒10 = 7.8 +2 PLSB           ∵ PLSB =PUSB ⇒PLSB = 1.1 kW  If we suppress  Pc  and  PLSB , then new Pt' = PUSB = 1.1 kW  So, saving in transmitted power  = 10 - 1.1 = 8.9 kW ∴Percentage saving = 8.910×100 = 89% II method %=Pc1+m24Pc(1+m22)×100=4+m24(2+m22)×100= 2+0.5625×100=89%