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Q.

When a photon of Lymann series, emitted from hydrogen atom falls on the metal surface of a photo electric cell having work function 6.044 eV. The maximum kinetic energy of the photoelectron is found to be 6.022 eV. The wavelength of radiation emitted from hydrogen atom belongs to

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a

first line of Lymann series

b

Second line of Lymann series

c

Third line of Lymann series

d

Fourth line of Lymann series

answer is B.

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Detailed Solution

13.61−1n2=ϕ+Kmax⇒ 13.61−1n2=6.022+6.022⇒n≃3
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