When photons of wavelength λ1 are incident on an isolated sphere, the corresponding stopping potential is found to be V. When photons of wavelength λ2 are used, the corresponding stopping potential was thrice that of the above value. If light of wavelength λ3 is used then find the stopping Potential for this case:
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a
hce1λ3+1λ2−1λ1
b
hce1λ3+12λ2−1λ1
c
hce1λ3−1λ2−1λ1
d
hce1λ3−32λ1+12λ2
answer is D.
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Detailed Solution
From Einstein’s photoelectric equation, we have hcλ1=hcλ0+eV ……..(1) hcλ2=hcλ0+3eV ……. (2)hcλ3=hcλ0+eV' ………. (3)From equation (1)& (2)32λ1−12λ2=1λ0 ⇒hcλ1−hc[32λ1−12λ2]=eV' ⇒hce[1λ3−32λ1+12λ2]=V'