When a plane polarized light is incident on a polariser with the plane of polarization making an angle θ with the axis of transmission of the polarizer, the intensity of emergent ray is found to be I. When the polariser is rotated in its plane through an angle of 90o, the intensity of emergent ray is found to be 2I intensity of the incident ray is
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a
2 I
b
5I
c
4 I
d
3 I
answer is D.
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Detailed Solution
I=I0cos2θ and 2I=I0cos2(θ±90o)∴ I+2I=I0(cos2θ+sin2θ)⇒I0=3I