When the planet Jupiter is at a distance of 824.7 million km from the earth, its angular diameter is measured to be 35.72' ' of arc. The diameter of Jupiter can be calculated as

Distance of Jupiter from earth (d) = 8247 . million km=824.7×106  kmAngular diameter of Juptier (θ)=35.73"But 10=60"=(60×60)"1"=(160×60)0=160×60×π180rad=3.1460×60×180rad1"=4.85×10−6  rad∴ Angular diameter of Jupiter (θ)=(35.72×4.85×10−6)radIf D is the diameter of the Jupiter then, angular diameter(θ)=Dd=(35.72×4.85×10−6)×82.47×106=142873=1.429×105  km