When the point of suspension of pendulum is moved, its period of oscillation

When point of suspension of pendulum is moved upwards,geff =g+a, geff >g and as T∝1/geff , hence T decreases.i.e., choice (1) is correct.When point of suspension of pendulum is moved downwards and a > 2g, then the pendulum oscillates with the bob  above the point of suspension and its time period becomes T = 2πla - g . If a >2g , T decreases.Hence option (2) is correct .In case of horizontal accelerationgeff =g2+a2,  i.e.,  geff >gi.e., again T decreases.