When a proton is accelerated in a cyclotron device, maximum energy attained by it is $$10$$ MeV. If radius of ‘Dee’ of the cyclotron is doubled and the magnetic field is doubled, then the maximum energy of on α$$-particle$$ when accelerated in the cyclotron will be

Question

Infinity Learn · Accepted Answer

Maximum kinetic energy attained by a charged particle when accelerated in the cyclotron is given by $$K=Q2B2R22m$$∴Kα$$Kp=Q$$α$$Qp2$$.Bα$$Bp2$$.Rα$$Rp2$$.mpmα $$=(2)2$$.(1/2)2$$.$$(2)2$$.$$(4) ⇒Kα$$=10$$×$$16$$ MeV $$=$$ $$160$$ MeV.

When a proton is accelerated in a cyclotron device, maximum energy attained by it is 10 MeV. If radius of ‘Dee’ of the cyclotron is doubled and the magnetic field is doubled, then the maximum energy of on α-particle when accelerated in the cyclotron will be

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