Q.

When a proton is accelerated in a cyclotron device, maximum energy attained by it is 10 MeV. If radius of ‘Dee’ of the cyclotron is doubled and the magnetic field is doubled, then the maximum energy of on α-particle when accelerated in the cyclotron will be

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a

240 MeV

b

80 MeV

c

160 MeV

d

20 Mev

answer is C.

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Detailed Solution

Maximum kinetic energy attained by a charged particle when accelerated in the cyclotron is given by K=Q2B2R22m∴KαKp=QαQp2.BαBp2.RαRp2.mpmα =(2)2.(1/2)2.(2)2.(4) ⇒Kα=10×16 MeV = 160 MeV.
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