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Q.

When a proton is accelerated through a potential difference of ‘V’ volt, its de Broglie wave length is λ. What will be the de Broglie wave length of an α -when accelerated through the same potential difference ?

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a

λ4

b

λ22

c

λ2

d

λ24

answer is B.

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Detailed Solution

12mu2=QV ⇒P22m=QV⇒p=2mQV ∴ λ=hp=h2mQV ∴λ1λ=mm1.QQ1=14.12=122⇒λ1=λ22.
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