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Q.

When radiation is incident on a photoelectron emitter, the stopping potential is found to be 9 volts. If e/m for the electron is 1.8 x 1011C kg-1  the maximum velocity of the ejected electrons is

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a

6×105ms-1

b

8×105ms-1

c

1.8×106ms-1

d

1.8×105ms-1

answer is C.

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Detailed Solution

12mvmax2=eVo⇒vmax=2emVo=2×18×1011×9=1.8×106m/s.
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