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When radiation of wavelength λ is used to illuminate a metallic surface, the stopping potential is V. When the same surface is illuminated with radiation of wavelength 3λ, the stopping potential is V4. If the threshold wavelength for the metallic surface is nλ ,then value of n will be

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Detailed Solution

eV=hcλ−ϕeV4=hc3λ−ϕsolving hcλ−ϕ=4hc3λ−ϕ⇒ϕ=hc9λ⇒hcλ0=hc9λ⇒λ0=9λ

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