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When a resistance of 2 ohm is connected across the terminals of a cell, the current is 0.5 A. When the resistance is increased to 5 ohm, the current is 0.25 A. The e.m.f. of the cell is
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Correct option is B
Since i=ER+r. we get0.5=E2+r ….(i)0.25=E5+r ….(ii)Dividing (i) by (ii), we get 2=5+r2+r ⇒ r=1Ω∴ 0.5=E2+1⇒ E=1.5 VSimilar Questions
An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengths and radii of the wires are in the ratio of (4/3) and (2/3), then the ratio of the currents passing through the wires will be
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