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Q.

When a resistance of 2 ohm is connected across the terminals of a cell, the current is 0.5 A. When the resistance is increased to 5 ohm, the current is 0.25 A. The e.m.f. of the cell is

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a

1.0 V

b

1.5 V

c

2.0 V

d

2.5 V

answer is B.

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Detailed Solution

Since i=ER+r.  we  get0.5=E2+r                        ….(i)0.25=E5+r                    ….(ii)Dividing (i) by (ii), we get 2=5+r2+r  ⇒  r=1Ω∴  0.5=E2+1⇒  E=1.5 V
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