First slide

Moving coil Galvanometer

Question

When a $12 Ω$ resistor is connected with a moving coil galvanometer, then its deflection reduces from 50 divisions to 10 divisions. The resistance of the galvanometer is

Easy

A

$24 Ω$
B

$36 Ω$
C

$48 Ω$
D

$60 Ω$

Solution

$\begin{array}{l} i_{g} = \frac{iS}{S + G_{g}} \Rightarrow 10 = \frac{50 \times 12 \times 40}{12 + G} \Rightarrow 12 + G = 60 \\ \Rightarrow G = 48 Ω \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App