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Q.

When a 12   Ω resistor is connected with a moving coil galvanometer, then its deflection reduces from 50 divisions to 10 divisions. The resistance of the galvanometer is

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a

24   Ω

b

36   Ω

c

48   Ω

d

60   Ω

answer is C.

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Detailed Solution

ig=    iSS+Gg  ⇒10 =  50 ×  12  ×  4012 +  G ⇒  12+G=60⇒   G=48   Ω
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