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When a 12   Ω resistor is connected with a moving coil galvanometer, then its deflection reduces from 50 divisions to 10 divisions. The resistance of the galvanometer is

a
24   Ω
b
36   Ω
c
48   Ω
d
60   Ω

detailed solution

Correct option is C

ig=    iSS+Gg  ⇒10 =  50 ×  12  ×  4012 +  G ⇒  12+G=60⇒   G=48   Ω

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