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When at rest, a liquid stands at the same level in the tubes as shown in the figure. But as indicated, a height difference h occurs when the system is given an acceleration a towards the right. Then h is equal to
detailed solution
Correct option is D
Let P1 and P2 be the pressures at the bottom of the left and right ends of the tube, respectively.Then F=P1−P2A=ρghAwhere A is the cross section of the tube.The mass of the liquid in the horizontal portion is m=ρLANow, F=ma⇒ ρghA=ρLAa∴ h=aLgTalk to our academic expert!
Similar Questions
A vessel containing liquid of density is accelerated horizontally with acceleration 10m/ s2 in a gravity free space. A small sphere of density 2 is released from rest
with respect to the vessel. Find the initial acceleration of the sphere with respect to the vessel:
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