First slide

Thermal expansion

Question

When a rod is heated from 25°C to 75°C, it expands by 1 mm. When a rod of same material but with 4 times the length is heated from 25°C to 50°C. The increase in length is

Moderate

A

1mm
B

1.5mm
C

1.6mm
D

2 mm

Solution

${As α}_{1} = α_{2} \Rightarrow \frac{e_{1}}{l_{1} {Δt}_{1}} = \frac{e_{2}}{I_{2} {Δt}_{2}}$

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