When a semi-conducting material is doped with an impurity, new acceptor levels are created. In a particular thermal collision, a valence electron receives an energy equal to 2 kT (k = Boltzmann Constant, T = Absolute Temperature) and just reaches one of the acceptor levels. Assuming that the energy of the electron was at the top edge of valence band and the temperature T is equal to 300 K . Find the energy of acceptor levels above the valence band.
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a
52 meV
b
41 meV
c
30 meV
d
25 meV
answer is A.
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Detailed Solution
Given : 2 kT = Energy gap between acceptor hand and valency band∴E=2×1.38×10−23×300 [ k =Boltzmann Constant]E=(2×1.38×3)×10−21 J=(6×1.381.6)×10−2110−19 eV=5.175×10−2 eV =5.175×101 meV≃52 meV