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Q.

When a short bar magnet is kept in  TanA   position on a deflection magnetometer, the magnetic needle Oscillates with a frequency  'f'  and the deflection produced is 450 . If the bar magnet is removed the frequency of oscillation of that needle is

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a

n2=f214

b

n2=f214

c

n2=f213

d

n2=f213

answer is B.

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Detailed Solution

We know, frequency = n=12πMBI∴ n ∝B ⇒n1n2=B1B2 Initially in presence of bar magnet, B1=B2+BH2⇒B1=BHtan45°)2+BH2⇒B1=2BH          Finally, after removing bar magnet,  B2=BH∴n1n2=2BHBH=214 ⇒n2=n1214=f214
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