When a slow moving neutron collides with Uranium 235 atom 23592U, following reaction occurs. 01n+92235U⟶92236U∗⟶4099Zr+52134Te+301nIf kinetic energy of neutrons is neglected (as it is very small), then the Q of reaction is 37 x K MeV. The value of K is _________. Use following data.mU235=235.0439 u, mn=1.0087 u,mZr99=98.9165 u, mTe134=133.9115 u.
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Detailed Solution
ΔM=mU235+mn1−mZr99+m(Te)134+3mn1=0.1985So, Q value of reaction isQ=ΔM×931.5=185MeV=37×5MeV