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When a solid sphere rolls without slipping down an inclined plane making an angle θ with the horizontal, the acceleration of its centre of mass is a. If the same sphere slides without friction, its

a
72a
b
57a
c
75a
d
52a

detailed solution

Correct option is C

Acceleration of the solid sphere when it rolls without slipping down an inclined plane is    a = g sinθ1+IMR2For a solid sphere, I = 25MR2a = g sinθ1+25 = 57g sin θAcceleration of the same sphere when it slides without friction down an same inclined plane is a' = gsin θDivide (ii) by (i), we get,  a'a = 75 or  a' = 75a

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