First slide

Photo Electric Effect

Question

When a source of light is kept at 0.5m from a photo cell, the cut off voltage is found to the V₀. If the distance of the source is doubled the cut off voltage will be

Easy

A

$\frac{V_{0}}{2}$
B

$V_{0}$
C

$2 V_{0}$
D

$\frac{V_{0}}{4}$

Solution

Intensity of incident radiation only changes when the distance between source of radiation and photocell was changed( $I \propto \frac{1}{r^{2}}$ ) ,
As stopping potential is independent of Intensity of incident radiation , hence stopping potential does not changed

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