When a source of light is kept at 0.5m from a photo cell, the cut off voltage is found to the V0. If the distance of the source is doubled the cut off voltage will be
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a
V02
b
V0
c
2V0
d
V04
answer is B.
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Detailed Solution
Intensity of incident radiation only changes when the distance between source of radiation and photocell was changed(I∝1r2) ,As stopping potential is independent of Intensity of incident radiation , hence stopping potential does not changed